Formulaire complet maths spé bac 2026
Toutes les formules à connaître par cœur le jour du bac. Aucune formule n'est donnée sur le sujet (sauf rares exceptions explicitement précisées).
Suites
Suites arithmétiques
u n + 1 = u n + r u n = u 0 + n r u n = u p + ( n − p ) r u_{n+1} = u_n + r \qquad u_n = u_0 + nr \qquad u_n = u_p + (n-p)r u n + 1 = u n + r u n = u 0 + n r u n = u p + ( n − p ) r
Somme : ∑ k = 0 n u k = ( n + 1 ) ⋅ u 0 + u n 2 \sum_{k=0}^{n} u_k = (n+1) \cdot \dfrac{u_0 + u_n}{2} ∑ k = 0 n u k = ( n + 1 ) ⋅ 2 u 0 + u n
Suites géométriques
u n + 1 = q ⋅ u n u n = u 0 ⋅ q n u n = u p ⋅ q n − p u_{n+1} = q \cdot u_n \qquad u_n = u_0 \cdot q^n \qquad u_n = u_p \cdot q^{n-p} u n + 1 = q ⋅ u n u n = u 0 ⋅ q n u n = u p ⋅ q n − p
Somme : ∑ k = 0 n u k = u 0 ⋅ 1 − q n + 1 1 − q \sum_{k=0}^{n} u_k = u_0 \cdot \dfrac{1 - q^{n+1}}{1 - q} ∑ k = 0 n u k = u 0 ⋅ 1 − q 1 − q n + 1 (si q ≠ 1 q \neq 1 q = 1 )
Limites de q n q^n q n
∣ q ∣ < 1 |q| < 1 ∣ q ∣ < 1 : lim q n = 0 \lim q^n = 0 lim q n = 0
q = 1 q = 1 q = 1 : lim q n = 1 \lim q^n = 1 lim q n = 1
q > 1 q > 1 q > 1 : lim q n = + ∞ \lim q^n = +\infty lim q n = + ∞
q ≤ − 1 q \leq -1 q ≤ − 1 : pas de limite
Limites et croissances comparées
Fonction x → + ∞ x \to +\infty x → + ∞ x → 0 + x \to 0^+ x → 0 + ln ( x ) \ln(x) ln ( x ) + ∞ +\infty + ∞ − ∞ -\infty − ∞ e x e^x e x + ∞ +\infty + ∞ 1 1 1 1 x \frac{1}{x} x 1 0 0 0 + ∞ +\infty + ∞
Croissances comparées :
lim x → + ∞ ln ( x ) x n = 0 lim x → + ∞ e x x n = + ∞ lim x → − ∞ x n e x = 0 \lim_{x \to +\infty} \frac{\ln(x)}{x^n} = 0 \qquad \lim_{x \to +\infty} \frac{e^x}{x^n} = +\infty \qquad \lim_{x \to -\infty} x^n e^x = 0 lim x → + ∞ x n l n ( x ) = 0 lim x → + ∞ x n e x = + ∞ lim x → − ∞ x n e x = 0
lim x → 0 + x ln ( x ) = 0 lim x → 0 + x n ln ( x ) = 0 ( n > 0 ) \lim_{x \to 0^+} x \ln(x) = 0 \qquad \lim_{x \to 0^+} x^n \ln(x) = 0 \quad (n > 0) lim x → 0 + x ln ( x ) = 0 lim x → 0 + x n ln ( x ) = 0 ( n > 0 )
Dérivées usuelles
f ( x ) f(x) f ( x ) f ′ ( x ) f'(x) f ′ ( x ) k k k 0 0 0 x n x^n x n n x n − 1 n x^{n-1} n x n − 1 1 x \frac{1}{x} x 1 − 1 x 2 -\frac{1}{x^2} − x 2 1 x \sqrt{x} x 1 2 x \frac{1}{2\sqrt{x}} 2 x 1 ln ( x ) \ln(x) ln ( x ) 1 x \frac{1}{x} x 1 e x e^x e x e x e^x e x cos ( x ) \cos(x) cos ( x ) − sin ( x ) -\sin(x) − sin ( x ) sin ( x ) \sin(x) sin ( x ) cos ( x ) \cos(x) cos ( x )
Opérations sur les dérivées
( u + v ) ′ = u ′ + v ′ ( u v ) ′ = u ′ v + u v ′ ( u v ) ′ = u ′ v − u v ′ v 2 (u + v)' = u' + v' \qquad (uv)' = u'v + uv' \qquad \left(\dfrac{u}{v}\right)' = \dfrac{u'v - uv'}{v^2} ( u + v ) ′ = u ′ + v ′ ( uv ) ′ = u ′ v + u v ′ ( v u ) ′ = v 2 u ′ v − u v ′
Dérivées composées
f ( x ) f(x) f ( x ) f ′ ( x ) f'(x) f ′ ( x ) e u ( x ) e^{u(x)} e u ( x ) u ′ ( x ) e u ( x ) u'(x) e^{u(x)} u ′ ( x ) e u ( x ) ln ( u ( x ) ) \ln(u(x)) ln ( u ( x )) (avec u > 0 u > 0 u > 0 )u ′ ( x ) u ( x ) \dfrac{u'(x)}{u(x)} u ( x ) u ′ ( x ) u ( x ) n u(x)^n u ( x ) n n u ′ ( x ) u ( x ) n − 1 n u'(x) u(x)^{n-1} n u ′ ( x ) u ( x ) n − 1 u ( x ) \sqrt{u(x)} u ( x ) (avec u > 0 u > 0 u > 0 )u ′ ( x ) 2 u ( x ) \dfrac{u'(x)}{2\sqrt{u(x)}} 2 u ( x ) u ′ ( x )
Exponentielle et logarithme
Propriétés algébriques de exp \exp exp
e a + b = e a e b e a − b = e a e b e − a = 1 e a ( e a ) n = e n a e^{a+b} = e^a e^b \qquad e^{a-b} = \dfrac{e^a}{e^b} \qquad e^{-a} = \dfrac{1}{e^a} \qquad (e^a)^n = e^{na} e a + b = e a e b e a − b = e b e a e − a = e a 1 ( e a ) n = e na
e 0 = 1 e x > 0 ∀ x ∈ R e^0 = 1 \qquad e^x > 0 \quad \forall x \in \mathbb{R} e 0 = 1 e x > 0 ∀ x ∈ R
Propriétés algébriques de ln \ln ln
ln ( a b ) = ln ( a ) + ln ( b ) ln ( a b ) = ln ( a ) − ln ( b ) \ln(ab) = \ln(a) + \ln(b) \qquad \ln\left(\dfrac{a}{b}\right) = \ln(a) - \ln(b) ln ( ab ) = ln ( a ) + ln ( b ) ln ( b a ) = ln ( a ) − ln ( b )
ln ( a n ) = n ln ( a ) ln ( 1 a ) = − ln ( a ) \ln(a^n) = n \ln(a) \qquad \ln\left(\dfrac{1}{a}\right) = -\ln(a) ln ( a n ) = n ln ( a ) ln ( a 1 ) = − ln ( a )
ln ( 1 ) = 0 ln ( e ) = 1 ln d e ˊ fini sur ] 0 , + ∞ [ \ln(1) = 0 \qquad \ln(e) = 1 \qquad \ln \text{ défini sur } ]0, +\infty[ ln ( 1 ) = 0 ln ( e ) = 1 ln d e ˊ fini sur ] 0 , + ∞ [
Réciprocité exp ↔ ln \exp \leftrightarrow \ln exp ↔ ln
ln ( e x ) = x ∀ x ∈ R e ln ( x ) = x ∀ x > 0 \ln(e^x) = x \quad \forall x \in \mathbb{R} \qquad e^{\ln(x)} = x \quad \forall x > 0 ln ( e x ) = x ∀ x ∈ R e l n ( x ) = x ∀ x > 0
Primitives usuelles
f ( x ) f(x) f ( x ) F ( x ) F(x) F ( x ) (+ C)k k k k x kx k x x n x^n x n (n ≠ − 1 n \neq -1 n = − 1 )x n + 1 n + 1 \frac{x^{n+1}}{n+1} n + 1 x n + 1 1 x \frac{1}{x} x 1 $\ln 1 x \frac{1}{\sqrt{x}} x 1 2 x 2\sqrt{x} 2 x e x e^x e x e x e^x e x e a x + b e^{ax+b} e a x + b 1 a e a x + b \frac{1}{a} e^{ax+b} a 1 e a x + b cos ( x ) \cos(x) cos ( x ) sin ( x ) \sin(x) sin ( x ) sin ( x ) \sin(x) sin ( x ) − cos ( x ) -\cos(x) − cos ( x )
Primitives par identification
f f f F F F u ′ ⋅ u n u' \cdot u^n u ′ ⋅ u n (n ≠ − 1 n \neq -1 n = − 1 )u n + 1 n + 1 \frac{u^{n+1}}{n+1} n + 1 u n + 1 u ′ u \frac{u'}{u} u u ′ (u > 0 u > 0 u > 0 )ln ( u ) \ln(u) ln ( u ) u ′ ⋅ e u u' \cdot e^u u ′ ⋅ e u e u e^u e u u ′ u \frac{u'}{\sqrt{u}} u u ′ (u > 0 u > 0 u > 0 )2 u 2\sqrt{u} 2 u u ′ u 2 \frac{u'}{u^2} u 2 u ′ − 1 u -\frac{1}{u} − u 1
Intégrales
∫ a b f ( x ) d x = F ( b ) − F ( a ) \int_a^b f(x) \, dx = F(b) - F(a) ∫ a b f ( x ) d x = F ( b ) − F ( a )
Propriétés :
∫ a a f = 0 ∫ a b f = − ∫ b a f ∫ a b f + ∫ b c f = ∫ a c f (Chasles) \int_a^a f = 0 \qquad \int_a^b f = -\int_b^a f \qquad \int_a^b f + \int_b^c f = \int_a^c f \text{ (Chasles)} ∫ a a f = 0 ∫ a b f = − ∫ b a f ∫ a b f + ∫ b c f = ∫ a c f (Chasles)
∫ a b ( f + g ) = ∫ a b f + ∫ a b g ∫ a b k f = k ∫ a b f \int_a^b (f + g) = \int_a^b f + \int_a^b g \qquad \int_a^b k f = k \int_a^b f ∫ a b ( f + g ) = ∫ a b f + ∫ a b g ∫ a b k f = k ∫ a b f
Valeur moyenne : μ = 1 b − a ∫ a b f ( x ) d x \mu = \dfrac{1}{b-a} \int_a^b f(x) \, dx μ = b − a 1 ∫ a b f ( x ) d x
Équations différentielles
y ′ = a y y' = ay y ′ = a y
Solutions : y ( x ) = C e a x y(x) = C e^{ax} y ( x ) = C e a x , C ∈ R C \in \mathbb{R} C ∈ R .
y ′ = a y + b y' = ay + b y ′ = a y + b (avec a ≠ 0 a \neq 0 a = 0 )
Solutions : y ( x ) = C e a x − b a y(x) = C e^{ax} - \dfrac{b}{a} y ( x ) = C e a x − a b , C ∈ R C \in \mathbb{R} C ∈ R .
Méthode : solution particulière constante y 0 = − b a y_0 = -\dfrac{b}{a} y 0 = − a b + solution homogène y h = C e a x y_h = C e^{ax} y h = C e a x .
Géométrie dans l'espace
Opérations sur les vecteurs
u ⃗ + v ⃗ = ( x + x ′ ; y + y ′ ; z + z ′ ) λ u ⃗ = ( λ x ; λ y ; λ z ) \vec{u} + \vec{v} = (x + x'; y + y'; z + z') \qquad \lambda \vec{u} = (\lambda x; \lambda y; \lambda z) u + v = ( x + x ′ ; y + y ′ ; z + z ′ ) λ u = ( λ x ; λ y ; λ z )
∥ u ⃗ ∥ = x 2 + y 2 + z 2 A B = ( x B − x A ) 2 + ( y B − y A ) 2 + ( z B − z A ) 2 \|\vec{u}\| = \sqrt{x^2 + y^2 + z^2} \qquad AB = \sqrt{(x_B - x_A)^2 + (y_B - y_A)^2 + (z_B - z_A)^2} ∥ u ∥ = x 2 + y 2 + z 2 A B = ( x B − x A ) 2 + ( y B − y A ) 2 + ( z B − z A ) 2
Produit scalaire
u ⃗ ⋅ v ⃗ = x x ′ + y y ′ + z z ′ = ∥ u ⃗ ∥ ⋅ ∥ v ⃗ ∥ cos ( u ⃗ , v ⃗ ^ ) \vec{u} \cdot \vec{v} = xx' + yy' + zz' = \|\vec{u}\| \cdot \|\vec{v}\| \cos(\widehat{\vec{u}, \vec{v}}) u ⋅ v = x x ′ + y y ′ + z z ′ = ∥ u ∥ ⋅ ∥ v ∥ cos ( u , v )
Orthogonalité : u ⃗ ⊥ v ⃗ ⇔ u ⃗ ⋅ v ⃗ = 0 \vec{u} \perp \vec{v} \Leftrightarrow \vec{u} \cdot \vec{v} = 0 u ⊥ v ⇔ u ⋅ v = 0
Carré scalaire : u ⃗ ⋅ u ⃗ = ∥ u ⃗ ∥ 2 \vec{u} \cdot \vec{u} = \|\vec{u}\|^2 u ⋅ u = ∥ u ∥ 2
Droites et plans
Droite passant par A A A , vecteur directeur u ⃗ ( a ; b ; c ) \vec{u}(a; b; c) u ( a ; b ; c ) :
{ x = x A + t a y = y A + t b z = z A + t c , t ∈ R \begin{cases} x = x_A + ta \\ y = y_A + tb \\ z = z_A + tc \end{cases}, \quad t \in \mathbb{R} ⎩ ⎨ ⎧ x = x A + t a y = y A + t b z = z A + t c , t ∈ R
Plan de vecteur normal n ⃗ ( a ; b ; c ) \vec{n}(a; b; c) n ( a ; b ; c ) passant par A A A :
a ( x − x A ) + b ( y − y A ) + c ( z − z A ) = 0 ⇔ a x + b y + c z + d = 0 a(x - x_A) + b(y - y_A) + c(z - z_A) = 0 \quad \Leftrightarrow \quad ax + by + cz + d = 0 a ( x − x A ) + b ( y − y A ) + c ( z − z A ) = 0 ⇔ a x + b y + cz + d = 0
Distance point-plan : d ( M , P ) = ∣ a x M + b y M + c z M + d ∣ a 2 + b 2 + c 2 d(M, P) = \dfrac{|ax_M + by_M + cz_M + d|}{\sqrt{a^2 + b^2 + c^2}} d ( M , P ) = a 2 + b 2 + c 2 ∣ a x M + b y M + c z M + d ∣
Probabilités
Probabilités conditionnelles
P A ( B ) = P ( A ∩ B ) P ( A ) P ( A ∩ B ) = P ( A ) ⋅ P A ( B ) = P ( B ) ⋅ P B ( A ) P_A(B) = \dfrac{P(A \cap B)}{P(A)} \qquad P(A \cap B) = P(A) \cdot P_A(B) = P(B) \cdot P_B(A) P A ( B ) = P ( A ) P ( A ∩ B ) P ( A ∩ B ) = P ( A ) ⋅ P A ( B ) = P ( B ) ⋅ P B ( A )
Si { A 1 , . . . , A n } \{A_1, ..., A_n\} { A 1 , ... , A n } est une partition de Ω \Omega Ω :
P ( B ) = ∑ i = 1 n P ( A i ) ⋅ P A i ( B ) P(B) = \sum_{i=1}^{n} P(A_i) \cdot P_{A_i}(B) P ( B ) = ∑ i = 1 n P ( A i ) ⋅ P A i ( B )
P B ( A ) = P ( A ) ⋅ P A ( B ) P ( B ) P_B(A) = \dfrac{P(A) \cdot P_A(B)}{P(B)} P B ( A ) = P ( B ) P ( A ) ⋅ P A ( B )
Indépendance
A A A et B B B indépendants ⇔ P ( A ∩ B ) = P ( A ) ⋅ P ( B ) \Leftrightarrow P(A \cap B) = P(A) \cdot P(B) ⇔ P ( A ∩ B ) = P ( A ) ⋅ P ( B ) ⇔ P A ( B ) = P ( B ) \Leftrightarrow P_A(B) = P(B) ⇔ P A ( B ) = P ( B )
Variables aléatoires
Espérance, variance, écart-type
E ( X ) = ∑ i x i p i V ( X ) = E ( X 2 ) − E ( X ) 2 σ ( X ) = V ( X ) E(X) = \sum_i x_i p_i \qquad V(X) = E(X^2) - E(X)^2 \qquad \sigma(X) = \sqrt{V(X)} E ( X ) = ∑ i x i p i V ( X ) = E ( X 2 ) − E ( X ) 2 σ ( X ) = V ( X )
Linéarité : E ( a X + b ) = a E ( X ) + b E(aX + b) = aE(X) + b E ( a X + b ) = a E ( X ) + b · V ( a X + b ) = a 2 V ( X ) V(aX + b) = a^2 V(X) V ( a X + b ) = a 2 V ( X )
Loi binomiale
X ∼ B ( n , p ) X \sim \mathcal{B}(n, p) X ∼ B ( n , p ) :
P ( X = k ) = ( n k ) p k ( 1 − p ) n − k , k ∈ { 0 , . . . , n } P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}, \quad k \in \{0, ..., n\} P ( X = k ) = ( k n ) p k ( 1 − p ) n − k , k ∈ { 0 , ... , n }
E ( X ) = n p V ( X ) = n p ( 1 − p ) σ ( X ) = n p ( 1 − p ) E(X) = np \qquad V(X) = np(1-p) \qquad \sigma(X) = \sqrt{np(1-p)} E ( X ) = n p V ( X ) = n p ( 1 − p ) σ ( X ) = n p ( 1 − p )
P ( X ≥ 1 ) = 1 − P ( X = 0 ) = 1 − ( 1 − p ) n P(X \geq 1) = 1 - P(X = 0) = 1 - (1-p)^n P ( X ≥ 1 ) = 1 − P ( X = 0 ) = 1 − ( 1 − p ) n
Inégalité de concentration
Pour M n = X 1 + . . . + X n n M_n = \dfrac{X_1 + ... + X_n}{n} M n = n X 1 + ... + X n (moyenne empirique de variables indépendantes de même loi, espérance μ \mu μ , variance σ 2 \sigma^2 σ 2 ) :
P ( ∣ M n − μ ∣ ≥ ε ) ≤ σ 2 n ε 2 P(|M_n - \mu| \geq \varepsilon) \leq \dfrac{\sigma^2}{n \varepsilon^2} P ( ∣ M n − μ ∣ ≥ ε ) ≤ n ε 2 σ 2
Algorithmes Python (modèles)
Calcul du n-ième terme d'une suite
def terme (n, u0 ):
u = u0
for k in range (n):
u = f(u)
return u
Seuil pour suite croissante
def seuil (S, u0 ):
u = u0
n = 0
while u < S:
u = f(u)
n = n + 1
return n
Seuil pour suite décroissante
def seuil (S, u0 ):
u = u0
n = 0
while u > S:
u = f(u)
n = n + 1
return n